Udemy Number of Deals Until Blackjack

#Shuffle the deck and deal 2 cards
#Check if you have blackjack
#Repeat process until you have blackjack
#How many times did you repeat the process until you had blackjack

#Below is the Udemy professor's solution

def shuffleDeck():
    cardDeck = ['A','K','Q','J','10','9','8','7','6','5','4','3','2',
            	'A','K','Q','J','10','9','8','7','6','5','4','3','2',
            	'A','K','Q','J','10','9','8','7','6','5','4','3','2',
            	'A','K','Q','J','10','9','8','7','6','5','4','3','2']
    returnDeck = [] # Empty list will be filled with random order of cards
    noCardsInDeck = 52
    
    import random
    while noCardsInDeck > 0: # when there aren't any cards left in deck it will exit loop
    	x = random.randint(0, noCardsInDeck-1) 
    	xCard = cardDeck[x]
    	returnDeck.append(xCard)
    	cardDeck.pop(x) # removes xCard from cardDeck
        noCardsInDeck = noCardsInDeck - 1 # Must decrease this so the x is not out of range
    
    return returnDeck # output of function is shuffled deck

def getcardValue(card): # calculates value of hand based on 11 for A and 10 for K,Q,J,10. 0 is for the rest of the cards.
    if card == "A":
        return 11
    if card == "K" or card == "Q" or card == "J" or card == "10":
        return 10
    return 0

total = 0 # calculates the total of the hand
count = 0 # counts how many hands until blackjack

while total != 21: # loop exit when blackjack (21) is found
    count += 1
    x = shuffleDeck() # here we assign the output of shuffleDeck() which is a shuffled deck to x
    total = getcardValue(x[0]) + getcardValue(x[1]) # here we use our 2 functions combined to get total of 2 cards

print "Number of deals until blackjack = " + str(count)

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