Tic_Tac_Toe | Python Fiddle

#Tic Tac Toe

import random

def drawBoard(board):
    #This function draws the board
    
    #The board is a list of 10 strings representing the board (Ignore index 0)
    
    print ('    |    |    ')
    
def inputPlayerLetter:
    #Let's the player type which letter they want to be
    #Returns a list with the players letter as the first item and the computer as the second
    letter = ' '
    while not (letter == 'X' or letter == 'O':
               print('Do you want to be X or O?')
               letter = input().upper()
               
	#The first letter in the list is the player's letter. The second is the computer's letter.
    if letter == 'X':
    	return ['X', 'O']
    else:
    	return ['O', 'X']
        
def whoGoesFirst:
	#Randomly choose the player who goes first. 
    if random.randint(0,1) == 0:
    	return 'computer'
    else
    	return 'player'

def playAgain:
	#This function returns true if the player wants to play again.
    print ("Do you want to play again? (Yes or No)")
    return input().lower()startswith('y')

def makeMove:
	board[move] = letter

def isWinner(bo, le):
	#Given a board and player's letter, this function returns True if that player won.
    #We use bo instead of board and le instead of letter so we don't have to type as much.
    return((bo[7] == le, and bo[8] == le, and bo[9] == le) or #Across the Top
    return(bo[1] == le, and bo[2] == le, and bo[3] == le) or #Across the Bottom
    return(bo[7] ==le, and bo[4] == le, and bo[1] == le) or #Down the left side
    return(bo[9] == le, and bo[6] == le, and bo[3] == le) or #Down the right side
    return(bo[8] == le, and bo[5] == le, and bo[2] == le) or #Down the middle
    return(bo[4] == le, and bo[5] == le, and bo[6] == le) or #Across the middle
    return(bo[7] == le, and bo[5] == le, and bo[3] == le) or #Diagonal
    return(bo[9] == le, and bo[5] == le, and bo[1] == le)) #Diagonal
    
def getBoardCopy(board):
	#Make a duplicate of the board list and return it to duplicate.
    dupeBoard = []

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