Print Graph python | Python Fiddle

import math
def f1(n):
    log = math.log(n, 2)
    answer = 'log(' + str(n) + ')=' + str(round(log, 1))
    return answer
def f2(n):
    log = (math.log(n, 2) ** 2)
    answer = 'log^2(' + str(n) + ')=' + str(round(log, 1))
    return answer
def f3(n):
    log = (n * math.log(n, 2))
    answer = str(n) + 'log(' + str(n) + ')=' + str(round(log, 1))
    return answer
def f4(n):
    power = math.pow(n,2)
    answer = str(n) + '^2' + '=' + str(int(power))
    return answer
def f5(n):
    power = math.pow(2,n)
    answer = '2^' + str(n) + '=' + str(int(power))
    return answer  
def f6(n):
    factorial = math.factorial(n)
    answer = str(n) + '!' + '=' + str(int(factorial))
    return answer  
def f7(n):
    power = math.pow(n, n)
    answer = str(n) + '^' + str(n) + '=' + str(int(power))
    return answer

def printGraph(func1, func2, n):
    answer = [(func1(x), func2(x)) for x in range(1, int(n+1))]
#    strAnswer = ' '.join([str(i) for i in answer])
#    strAnswer = ' '.join(map(str, answer))
#    answer.tanslate(None, ",()")
#    print(answer[0][0] + '\t' + answer[0][1])
#    print(answer[1][0] + '\t' + answer[1][1])
#    print(answer[2][0] + '\t' + answer[2][1])
#    print(answer[3][0] + '\t' + answer[3][1])
#    print(answer[4][0] + '\t' + answer[4][1])
#    [print(i, j) for i in answer for j in answer]
    for i in range(0, int(n)):
        print(answer[i][0] + '\t\t' + answer[i][1])
#    print(strAnswer + '\n')

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