Naive String Search | Python Fiddle

"""Write a function match() that takes two arguments. 
The first argument is a string representing a pattern and the second
argument is a string representing some text. The function returns true
if the characters in the pattern match exactly against a substring of the
text. Otherwise it returns false. You can use any programming or scripting 
language that will run from a Linux shell. You should not use any string or
regular expression functions, apart from the following:
* A function to get the length of a string
* A function to return the Nth character in a string
Your code should compile and run without any modifications."""

def match(pattern, text):
  contains_text = False
  t_index = 0
  p_index = 0
  while t_index < len(text) and not contains_text:
    if pattern[p_index] == text[t_index]:
      p_index += 1
      if p_index == len(pattern):
        contains_text = True
    else:
      if p_index > 0:
        p_index = 0      
    t_index += 1
  return contains_text
    
    
print match('asg', 'dasf')

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