MinMax | Python Fiddle

def minMax(L):

n = len(L) 
	counter = 0
	if n == 0:
		return

elif n == 1:
		min = max = L[0]

elif n == 2:
		# 1 compare for 2 elements
		counter +=1
		if L[0] < L[n-1]:
			min = L[0]
			max = L[n-1]
		else:
			min = L[n-1]
			max = L[0]  
	
	else:

# 1 compare between 1st and last element
		counter +=1
		if L[0] < L[n-1]:
			min = L[0]
			max = L[n-1]
		else:
			min = L[n-1]
			max = L[0]

mid = int((n-2)/2) + ((n-2) % 2 > 0)

for i in range (1,mid+1): 
			# maximum 3 compares for any 2 elements
			counter += 1
			if L[i] < L[n-i-1]:
				counter += 1
				if L[i] < min:
					min = L[i]
				counter += 1
				if L[n-i-1] > max:
					max = L[n-i-1]

else:
				counter += 1
				if L[n-i-1] < min:
					min = L[n-i-1]
				counter += 1
				if L[i] > max:
                    
					max = L[i]
	print "\noriginal list: " , str(L)[1:-1]
	print "min: " , min
	print "max: " , max
	print "Length of list: " , n
	print "total comparisons: ", counter , "\n"

def main():

minMax([9, 3, 5, 10, 1, 7, 12])
	#minMax([5,78,99,4,890,76543,8])
	#minMax([9, 3, 5, 10, 1, 7])
	#minMax([1, 3, 5, 8, 4, 10])
	#minMax([10, 3, 5, 8, 7, 1])
	#minMax([4, 3, 5, 1, 7, 10])
	minMax([9, 3, 5, 10, 1, 7 , 5,78,99,4,890,76543,8,67,89,34,2,1,6,7,0,56,58]) 
	minMax([])
	minMax([3])
	minMax([5,4])
	minMax([5,4,3])

if __name__ == "__main__":
	main()

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