List Item Removal | Python Fiddle

def remove_values_from_list(the_list, val):
    return [value for value in the_list if value != val]

def remove_consumpton_from_list(the_list, val):
    return [value for value in the_list if 'keyName' in value and value['keyName'] == 'consumption']

x = [1, 2, 3, 4, 2, 2, 3]
x = remove_values_from_list(x, 2)
print x
# [1, 3, 4, 3]

propertyInputs = [{'keyName': 'rando', 'dataValue': 1}, {'keyName': 'notMe', 'dataValue': 2}, {'keyName': 'consumption', 'dataValue': 100}, {'keyName': 'consumption', 'dataValue': 200}]
# z = [value for value in y if y['keyName'] != 'consumption']
# print z
# [1, 3, 4, 3]

for i, propertyInput in propertyInputs:
    if 'keyName' in propertyInput and propertyInput['keyName'] == 'consumption':
		print propertyInput
    else:
    	print "dunno mate"

print propertyInputs

new_one = [x for x in propertyInputs if 'keyName' in x and x['keyName'] != 'consumption']

print new_one

tariffComparisonRequest = {
	'groupBy': 'ALL',
	'detailLevel': 'RATE',
	'billingPeriod': True,
	'minimums': True,
	'scenarios': [],
	'sharedScenario': {
		'propertyInputs': [{
			'keyName': 'hasCaliforniaClimateCredit',
			'dataValue': False
		}]
	}
}

tariffComparisonRequest['sharedScenario']['propertyInputs'] = [x for x in tariffComparisonRequest['sharedScenario']['propertyInputs'] if 'keyName' in x and x['keyName'] != 'consumption']

print tariffComparisonRequest

Browser Version Not Supported

Due to Python Fiddle's reliance on advanced JavaScript techniques, older browsers might have problems running it correctly. Please download the latest version of your favourite browser.
Chrome 10+ Firefox 4+ Safari 5+
IE 10+

Let me try anyway!

Python Fiddle

Python Cloud IDE