Links finder problem | Python Fiddle

# Modify the get_next_target procedure so that
# if there is a link it behaves as before, but
# if there is no link tag in the input string,
# it returns None, 0.

# Note that None is not a string and so should
# not be enclosed in quotes.

# Also note that your answer will appear in
# parentheses if you print it.

page = '3gewlkf <a href="http:udacity.com" 3tjfekljad <a href="http:wawa.com">fdagae'

#this bit tests whether there is a link or not. If there is a link it outputs url string, and end_quote position
#if no links then outputs None condition

def get_next_target(page):
    start_link = page.find('<a href=')

if start_link == -1:
        return None, 0
   
    start_quote = page.find('"', start_link)
    end_quote = page.find('"', start_quote + 1)
    url = page[start_quote + 1:end_quote]
    return url, end_quote

#this bit sets the condition to go back to get_next_target until result gives None condition, in which case it breaks.

def print_all_links(page):
    while True:
        url, endpos = get_next_target(page)
        if url:
            print url
            page = page[endpos:]
        else:
            break
            
print_all_links(page)

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