LCD and LCM finder | Python Fiddle

# LCD/M Finder
# Version: 0.10
# Released: 3/7/14 4:10 PM
# Program developed by James Sobolewski
#
# NOTES:
# - Program does not currently support more than two denominators
# or variables.
#################################################################
# Print Program Header
print("LCD/M Finder\nVersion: 0.10\nReleased: 3/7/14 4:10 PM")
print("************************************************************")
# Declare and initialize variables
setverbose = "null"
# Get preference inputs
setverbose = raw_input("Specify y for verbose (detailed) output, otherwise press enter: ")
if setverbose == "y":
    print("VERBOSE ON: Extremely large numbers may take more time if verbose is desired.")
print("************************************************************")
# Create perpetual loop.
while 1 == 1:
# Declare and reset variables
    den1 = 0
    den2 = 0
    LCD = int(1)
    mult1 = 1
    mult2 = 1
    # Get inputs
    den1 = int(input("Enter the first denominator: "))
    den2 = int(input("Enter the second denominator: "))
    if setverbose == "y":
        print("----------------------------------------------------")
    # Determine if one of the denominators is a multiple/divisor.
    if (den1 % den2) == 0:
        if setverbose == "y":
            print("Remainder Test Pass: denominator 1 passed by denominator 2.")
        LCD = den1
    else:
        if setverbose == "y":
            print("Remainder Test Fail: denominator 1 failed by denominator 2.")
    if (den2 % den1) == 0:
        if setverbose == "y":
            print("Remainder Test Pass: denominator 2 passed by denominator 1.")
        LCD = den2
    else:
        if setverbose == "y":
            print("Remainder Test Fail: denominator 2 failed by denominator 1.")
    '''
    # DEVELOPMENT IN PROGRESS THIS AREA
    if den1 < den2:
        LCD = den1 * 2
    elif den2 < den1:
        LCD = den2 * 2
    '''
    # Determine if LCD has already been found
    while (den1 * mult1) != (den2 * mult2):
    # Test to see if the division returns a whole number
        if (LCD % den1) != 0:
            if setverbose == "y":
                print("Tried LCD: " + str(LCD)+". Failed to satisfy denominator 1.")
            LCD = LCD + 1
        elif (LCD % den2) != 0:
            if setverbose == "y":
                print("Tried LCD: " + str(LCD)+". Failed to satisfy denominator 2.")
            LCD = LCD + 1
        else:
            # Calculate multiple values
            mult1 = LCD / den1
            mult2 = LCD / den2
    # Print Data
    if setverbose == "y":
        print("Found LCD: " + str(LCD)+". Satisfies all denominators.")
    print("--------------------------------------------------------")
    print("LCD: " + str(LCD))
    print("Denominator 1 multiple: " + str(int(mult1)))
    print("Denominator 2 multiple: " + str(int(mult2)))
    print("========================================================")
    # Perpetual loop will restart.
# END OF FILE

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