frank | Python Fiddle

from datetime import date
from datetime import time
from datetime import datetime
from datetime import timedelta              #this is new

# construct a basic timedelta and print it
print timedelta(days=365, hours=5, minutes=1)

# print today's date
print "today is: " + str(datetime.now())

# print today's date one year from now
print "one year from now it will be: " + str(datetime.now() + timedelta(days=365))              # a plus 365

# create a timedelta that uses more than one argument
print "in two weeks and 3 days it will be: " + str(datetime.now() + timedelta(weeks=2, days=3))							#time delta 4 zones you can use
																												#to add
# calculate the date 1 week ago, formatted as a string
t = datetime.now() - timedelta(weeks=1)
s = t.strftime("%A %B %d, %Y")
print "one week ago it was " + s

### How many days until April Fools' Day?																#afd = april fools day

today = date.today()  # get today's date
afd = date(today.year, 4, 1)  # get April Fool's for the same year									#today.year separation    #if today.year is less than
# use date comparison to see if April Fool's has already gone for this year							#todays version of today.year than thing applies
# if it has, use the replace() function to get the date for next year
if afd < today:
  print "April Fool's day already went by %d days ago" % ((today-afd).days)
  afd = afd.replace(year=today.year + 1)  # if so, get the date for next year

# Now calculate the amount of time until April Fool's Day  
time_to_afd = abs(afd - today)
print time_to_afd.days, "days until next April Fools' Day!"											#just minus afd by current

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