Finding hours difference

# assuming clock runs from 0 to 23

time1 = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
time2 = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]

def timeOverlap(t1Start, t1End, t2Start, t2End):
    time1 = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
    time2 = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
    result = 0
    
    # process time1
    if t1End > t1Start: #t1 does not cross 0000
        for n in range(t1Start, t1End+1):
            time1.pop(n)
            time1.insert(n,1)
    elif t1End < t1Start: #t1 cross 0000
        for n in range(t1Start, 24):
            time1.pop(n)
            time1.insert(n,1)
        for n in range(0, t1End+1):
            time1.pop(n)
            time1.insert(n,1)

# process time2 this portion can be refractored out
    if t2End > t2Start: #t2 does not cross 0000
        for n in range(t2Start, t2End+1):
            time2.pop(n)
            time2.insert(n,1)
    elif t2End < t2Start: #t2 cross 0000
        for n in range(t2Start, 24):
            time2.pop(n)
            time2.insert(n,1)
        for n in range(0, t2End+1):
            time2.pop(n)
            time2.insert(n,1)

# compare time overlap
    for n in range(0,24):
        if time1[n] + time2[n] == 2:
            result = result + 1
        
    return result

print timeOverlap(7,10,9,11) # 1
print timeOverlap(8,10,9,12) # 1
print timeOverlap(2,20,1,21) # 
print timeOverlap(22,2,1,23) # 2

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