Far to Cel | Python Fiddle

#(°C × 9/5) + 32 = °F or in plain English, Multiple by 9, then divide by 5, then add 32.
#(°F - 32) x 5/9 = °C or in plain English, First subtract 32, then multiply by 5, then divide by 9.

#Variables: cel(Celsius) far(Fahrenheit)
repeat="true"
while repeat=="true":
    print("Please choose an option:-")
    print("1. Celsius to Fahrenheit")
    print("2. Fahrenheit to Celcius")
    
    option=input("Please Choose Now:")
    if option == "1":
        print("Celcius to Fahrenheit")
        print("Please enter in a value.")
        value=input()
        value2=int(value)*9
        value3=int(value2)/5
        answer=int(value3)+32
        print(value+ " Celcius is equal to " + str(answer) + " Fahrenheit")
        print("Do you wish to convert again?")
        option2=input("Y or N")
        if option2 == "Y":
            repeat=="true"
        elif option2 == "N":
            print("Have a nice day!")
            repeat="false"
            exit()
        else option2 != 
    elif option == "2":
        print("Fahrenheit to Celcius")
        print("Please enter in a value.")
        value=input()
        value2=int(value)-32
        value3=int(value2)*5
        answer=int(value3)/9
        print(value + " Fahrenheit is equal to " + str(answer) + " celcius")
        print("Do you wish to convert again?")
        option2=input("Y or N")
        if option2 == "Y":
            repeat=="true"
        elif option2 == "N":
            print("Have a nice day!")
            repeat="false"
            exit()
    else:
        print("Error must be 1 or 2")

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