#colon indicates that your starting the scope of the fcntion def func1(): print "I am a function" #defining arguments with funtion def func2(arg1, arg2): print arg1, " ", arg2 #function that returns a value #def cube(x): # return x*x*x #function with default value for an argument def power(num, x=1): result = 1; for i in range(x): result = result * num return result #function with variable number of arguments def multi_add(*args): result = 0; for x in args: result = result + x return result #func1() #print func1() #print func1 #func2(10,20) #print func2(10,20) #print cube (3) #no return values becomes NONE #print power(2) #print power(2, 3) #print power(x=4, num=2) print multi_add(4,5,10,4)
Run
Reset
Share
Import
Link
Embed
Language▼
English
中文
Python Fiddle
Python Cloud IDE
Follow @python_fiddle
Browser Version Not Supported
Due to Python Fiddle's reliance on advanced JavaScript techniques, older browsers might have problems running it correctly. Please download the latest version of your favourite browser.
Chrome 10+
Firefox 4+
Safari 5+
IE 10+
Let me try anyway!
url:
Go
Python Snippet
Stackoverflow Question
