''' Write a program, which will find all such numbers between 1000 and 3000 (both included) such that each digit of the number is an even number. The numbers obtained should be printed in a comma-separated sequence on a single line. ''' import math N1 = 2000 N2 = 3000 pow10 = range(int(math.ceil(math.log(max(N1, N2), 10)))) numlst = [] for i in range(N1, N2+1): k=i even = False check = True for j in pow10[::-1]: if j>0: digit = k/(10**j) k-=digit*(10**j) else: digit = k if digit%2==1: even = False; break else: even = True if even == True: numlst.append(i) print numlst
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