days old R2 | Python Fiddle

def isLeapYear(year):
    four = year/4.00
    hundred = year/100.0
    four_hundred = year/400.0
    if ((four%1) * 10) != 0.0:
        return False
    else:
        if ((hundred%1) * 10) != 0.0:
            return True
        else:
            if ((four_hundred%1) * 10) != 0.0:
                return False
            else:
                return True

daysOfMonths = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

def daysBetweenDates(y1, m1, d1, y2, m2, d2):
    if y1 > y2:
        return 'Calculation not possible! Birth date is later than current.'
    if y1 == y2:
        if m1 > m2:
            return 'Calculation not possible! Birth date is later than current.'
        if m1 == m2:
            if d1 > d2:
                return 'Calculation not possible! Birth date is later than current.'
    	else:
            born = daysOfMonths[m2-1] - daysOfMonths[m1-1]
            return born
    year_count = 0
    if y1+1 < y2:
        y1 = y1 + 1
    	while y1 < y2:
    		if isLeapYear(y1) == True:
       			days = 366
    		else:
       			days = 365
    		year_count = year_count + days
    		y1 = y1 + 1
    born_year = 0
    i = m1
    if isLeapYear(y1) == True:
    	daysOfMonths[1] = 29
    else:
    	daysOfMonths[1] = 28
    while i < len(daysOfMonths):
       	born_year = born_year + daysOfMonths[i]
       	i = i + 1
	born = born_year + (daysOfMonths[m1-1]-d1)
    current_year = 0
    i = 0
    if isLeapYear(y2) == True:
    	daysOfMonths[1] = 29
    else:
    	daysOfMonths[1] = 28
    while i < m2-1:
       	current_year = current_year + daysOfMonths[i]
       	i = i + 1
	current = current_year + d2
    return (year_count + born + current)

print daysBetweenDates(2015, 6, 27, 2015, 7, 24)

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