# This is a comment # # Simple implementation of a singly linked list # class Node(object): def __init__(self, data=None, nextNode=None): self.data = data self.nextNode = nextNode class linkedList(object): def __init__(self, head=None): self.head = head self.size = 0 def insert(self, node): if not self.head: self.head = node self.size += 1 else: # set new nodes pointer to old head node.nextNode = self.head # reset head to new node self.head = node self.size +=1 def getSize(self): return self.size def printLL(self): mynode = self.head c = 0 while mynode: c +=1 print(mynode.data c) mynode = mynode.nextNode def getNum(self, lList, Node): if self.head == Node: return self.head else: if lList.head.nextNode: self.search(linkedList(lList.head.nextNode), value) else: raise ValueError("Node not in Linked List") MyList = linkedList() MyList.insert(Node("Lars")) MyList.insert(Node("Alex")) print(MyList.getSize()) MyList.insert(Node("Michael")) print(MyList.getSize()) MyList.insert(Node("Abhi")) # Use my print method MyList.printLL() print('\n') MyList.getNum(2)
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