counting & sorting | Python Fiddle

gList = ["A","A","C","C","B"]
bucket = []
candy = {}
list = []
x = 0
for g in gList:
    if g not in bucket:
         # go thru each item in gList. 
         # When it sees an item not in bucket, it appends it to bucket.
        bucket.append(g)
         # bucket will only have one item from which to count repeated letters in gList.
         #.count() method returns count of how many times obj occurs in list.        
        theCount = gList.count(bucket[0])
         #print "theCount one", theCount
         # make the candy dictionary
        candy[str(bucket[0])]=theCount
         # delete it from list so it will start over.
        del bucket[0]
        a = candy[candy.keys()[x]]
        x = x + 1
        print x
        b = candy[candy.keys()[x]]
        print "this is a", a
        print "this is b", b
        print x
        #if a == b:
            #print "YEEEES"
print candy
for k, v in candy.iteritems():
    	list.append(v)
        if v not in list:
            me = False
        
        else:
            me = True
            srt = sorted(candy.items(), key=lambda t: t[1])
            theOne = len(srt) -1
            theWinner = srt[theOne]
        
        
print me
if me == False:
    print "Its is a tie"
else:
    print theWinner[0]

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