# Josh Roybal # CIS 122 # Chapter 13 Programming Exercise #6 def ackermann(m, n): if m == 0: return n + 1 elif n == 0: return ackermann(m - 1, 1) else: print(m, n) #included print function to display recursion return ackermann(m - 1, n - 1) m = 10 n = 10 print(ackermann(m, n))
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