def digit_sum(n): last = n // 10( n % 10) first = n / 10 digit_sum = first + last return digit_sum(93) print digit_sum #HINT: #One way might be to convert the integer to a string with str(), iterate over it, and turn the substrings back into integers with int() to do the addition. #If you're looking for a challenge, try this: to get the rightmost digit of a number, you can modulo (%) the number by 10. To remove the rightmost digit #you can floor divide (//) the number by 10. (Don't worry if you're not familiar with floor division—you can look up the documentation here. Remember, this is a challenge!) #Try working this into a pattern to isolate all of the digits and add them to a total.
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