Calendar Frenzy | Python Fiddle

#--- Calendars ---
	#For some reason the compiler for this one fs up hard I think its because all these are calendar conflict eachother
import calendar

# create a plain text calendar
c = calendar.TextCalendar(calendar.SUNDAY)  						#The sunday Represents first day #2013 year
str = c.formatmonth(2013, 1, 0, 0)											#1month which will spelled out in compiler
print str																#0,0i dont really know

# create an HTML formatted calendar################################################################################
hc = calendar.HTMLCalendar(calendar.SUNDAY)						This totally f up in example
str = hc.formatmonth(2013, 1)
print str

# loop over the days of a month###########################################################################################
# zeroes mean that the day of the week is in an overlapping month
for i in c.itermonthdays(2013, 8):
  print i																		#i = loop     
    						#Starts with a list of days in which beginning days  that dont belong to the monthwill have 0
  							#it will just list the numbers wont exactly loop
    
    
    
    
    
    
    
    
# The Calendar module provides useful utilities for the given locale,###########################################################
# such as the names of days and months in both full and abbreviated forms
for name in calendar.month_name:
  print name

for day in calendar.day_name:
  print day
    
    																#i = loop       #But in this case its name and day
    						#Starts with a list of days in which beginning days  that dont belong to the monthwill have 0
  							#it will just list the numbers wont exactly loop
    
    
    
    
    
    
    
    
    
 ############################################################################################################################

# Calculate days based on a rule: For example, consider
# a team meeting on the first Friday of every month.
# To figure out what days that would be for each month,
# we can use this script:
for m in range(1,13):																	#Range of months
  # returns an array of weeks that represent the month
  cal = calendar.monthcalendar(2013, m)											#Amount weeks
  # The first Friday has to be within the first two weeks
  weekone = cal[0]																#We are just interested in the friday
  weektwo = cal[1]
    
    
   
  if weekone[calendar.FRIDAY] != 0:
    meetday = weekone[calendar.FRIDAY]
  else:
    # if the first friday isn't in the first week, it must be in the second       #This is a if / else statement
    meetday = weektwo[calendar.FRIDAY]
   #%10 spaces  #%2 spaces
  print "%10s %2d" % (calendar.month_name[m], meetday)   #Result is something like  August 2

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