calculate your age in days

# By Websten from forums
#
# Given your birthday and the current date, calculate your age in days. 
# Account for leap days. 
#
# Assume that the birthday and current date are correct dates (and no 
# time travel). 
#

def leap_year(year):
    if year%4==0:
        if year%100==0:
            if year%400==0:
                return True
            else:
                return False
        else:
            return True
    else:
        return False

def daysBetweenDates(year1, month1, day1, year2, month2, day2):
    ##
    date1=(month1-1)*30+day1
    date2=(month2-1)*30+day2+(year2-year1)*365
        
    if leap_year(year1)==True:
        if month1>2:
            date1=date1+1
        
    year=year1
    while year<year2:
        if leap_year(year)==True:
            date2=date2+1
        year=year+1
    
    if leap_year(year2)==True:
        if month2>2:
            date2=date2+1
    
    month=1
    while month<month1:
        if month==1 or month==3 or month==5 or month==7 or month==8 or month==10:
            date1=date1+1
        if month==2:
            date1=date1-2
        month=month+1    
    
    month=1
    while month<month2:
        if month==1 or month==3 or month==5 or month==7 or month==8 or month==10:
            date2=date2+1
        if month==2:
            date2=date2-2
        month=month+1
    
    age=date2-date1
        
    return age
    
    ##
# Test routine

def test():
    test_cases = [((2012,1,1,2012,2,28), 58), 
                  ((2012,1,1,2012,3,1), 60),
                  ((2011,6,30,2012,6,30), 366),
                  ((2011,1,1,2012,8,8), 585 ),
                  ((1900,1,1,1999,12,31), 36523)]
    for (args, answer) in test_cases:
        result = daysBetweenDates(*args)
        if result != answer:
            print "Test with data:", args, "failed"
        else:
            print "Test case passed!"

test()

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